Is the given point interior, exterior, or on the circle (x + 2)2 + (y - 3)2 = 81? P(8, 4)
1 answer:
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
You might be interested in
(a + 2b) • (a2 - 2ab - 4b2)
Answer:
its C.
Step-by-step explanation:
i took the test
3cd^2(6cd + 14cd^2)
18cd^3 + 42cd^4
70/9
7 is equivalent 63/9, and then you add 63 and 7 to get 70/9
Step-by-step explanation:
y = -( 2+2)
- to find the intercept/ zero substitute y=0
- 0 = -(x-2+2) solve the equation for x
- x = 0