The exponential growth in biology is A=Pert, where "A" is the ending amount of whatever you're dealing with , "P" is the beginning amount of that same "whatever", "r" is the growth or decay rate, and "t" is time. The formula is related to the compound-interest formula, and represents the case of the interest being "compounded continuously".
Answer:
Step-by-step explanation:
From the picture attached,
Addition of the blocks in first row is 60
a + a + a + 12 = 60
3a + 12 = 60
3a = 60 - 12
3a = 48
a = 16
For second row,
(b + 5) + (b + 5) + (b + 5) + (b + 5) = 60
4(b + 5) = 60
b + 5 = 15
b = 10
For third row,
(a + b) + c = (b + 5) + (b + 5) + (b + 5)
a + b + c = 3(b + 5)
16 + 10 + c = 3(10 + 5) [Since, a = 16 and b = 10}
26 + c = 45
c = 45 - 26
c = 19
For fourth row,
3c + d = 60
3(19) + d = 60
57 + d = 60
d = 60 - 57
d = 3
Answer: The test contains 10 three-point questions and 14 five-point questions.
Step-by-step explanation:
Let x represent the number of 3-point questions.
Let y represent the number of 5-point questions.
The maths test consists of 24 questions. This means that
x + y = 24
Each question is worth either 3 points or 5 and the test is worth 100 points. This means that
3x + 5y = 100 - - - - - - - - - - -1
Substituting x = 24 - y into equation 1, it becomes
3(24 - y) + 5y = 100
72 - 3y + 5y = 100
- 3y + 5y = 100 - 72
2y = 28
y = 28/2 = 14
Substituting y = 14 into x = 24 - y , it becomes
x = 24 - 14 = 10
Answer:
4
Step-by-step explanation:
ΔABC is congruent with ΔDEF. That means the corresponding sides are congruent.
Look at the order of the letters. EF are the last two letters of ΔDEF. So this corresponds with the last two letters of ΔABC. Therefore, EF ≅ BC.
EF ≅ BC
x² + 8x = 48
x² + 8x − 48 = 0
(x + 12) (x − 4) = 0
x = -12 or 4
Since x can't be negative, x = 4.
