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Elena-2011 [213]
3 years ago
8

If you can get an answer to any question, what would you ask? You toss a fair coin 4 times. What is the probability that (round

to 4 decimal places) a) you get all Heads? b) you get at least one Tail?
Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answers:

a) 0.0625

b) 0.9375

==================================================

Work Shown:

The probability of landing on heads is 1/2 = 0.5 since both sides are equally likely to land on. Getting 4 heads in a row is (1/2)^4 = (0.5)^4 = 0.0625

The event of getting at least one tail is the complement of getting all four heads. This is because you either get all four heads or you get at least one tail. One or the other must happen. We subtract the result we got from 1 to get 1-0.0625 = 0.9375

You can think of it like this

P(getting all four heads) + P(getting at least one tail) = 1

The phrasing "at least one tail" means "one tail or more".

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kirill [66]

Answer:

V = 38659.68 cm^3

Step-by-step explanation:

If we pretend A barrel is a cylinder we use V=πr^2h for the volume.  We know h, but we need to find r

The question tells us the circumference, well how do we find circumference? C = 2πr, so we can use this to find r.

C = 2πr

56.52 = 2 * 3.14 * r Here divide both sides by 2*3.14

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Now we can just plug into the volume.

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I feel I should mention this is all true if the circumference is in centimeters, since the question didn't specify.  

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5 0
3 years ago
Mason plays a game by flipping two fair coins.He wins the game if both coins land facing heads up. If Mason plays 200 times, how
blagie [28]

Answer:

Therefore Mason would be expected to win 50 times.

Step-by-step explanation:

i) probability of flipping a head for a fair coin is \frac{1}{2}

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iii) Therefore if Mason plays 200 times he would be expected to win

    = \frac{1}{4} \times 200 =  50\hspace{0.1cm} times.

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