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3 years ago

How do i resolve this?

Mathematics

1 answer:

EleoNora [17]3 years ago

3 0

Solve for y for both equations then equate and solve:

5x + 9y = 160
9y = 160 - 5x
y = 160/9 - 5/9x

9x + 8y = 202
8y = 202 - 9x
y = 202/8 - 9/8x

160/9 - 5/9x = 202/8 - 9/8x (common denominator is 72)

1280/72 - 40/72x = 1818/72 - 81/72x
1818/72 - 1280/72 = 81/72x - 40/72x
538/72 = 41/72x
538 = 41x
538/41 = x
x = 13 5/41

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HELPP!!

Mamont248 [21]

Answer:

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6.

Step-by-step explanation:

5 0

2 years ago

What are the steps to this equation

Harlamova29_29 [7]

Answer:

$x=7$

Step-by-step explanation:

$\frac{2}{5}x+\frac{1}{3}=\frac{1}{3}x+\frac{4}{5}$

Subtract $\frac{1}{3}$ from both sides:

$\frac{2}{5}x+\frac{1}{3}-\frac{1}{3}=\frac{1}{3}x+\frac{4}{5}-\frac{1}{3}$

$\frac{2}{5} x=\frac{1}{3}x+\frac{12}{15}-\frac{5}{15}$

$\frac{2}{5}x=\frac{1}{3}x+\frac{7}{15}$

Subtract $\frac{1}{3} x$ from both sides:

$\frac{2}{5}x-\frac{1}{3}x=\frac{1}{3}x+\frac{7}{15}-\frac{1}{3}x$

$\frac{6}{15}x-\frac{5}{15}x=\frac{7}{15}$

$\frac{1}{15}x=\frac{7}{15}$

Multiply both sides by 15:

$15\times \frac{1}{15}x=\frac{7\times 15}{15}$

$x=\frac{105}{15}$

$x=7$

6 0

3 years ago

Read 2 more answers

X < -10/3 or x > 2/3

Fittoniya [83]

Hello! :)

Here is a graph for x < -10/3 or x > 2/3.

THEDIPER

6 0

3 years ago

The director of the library calculates that 29% of the library's collection is checked out. If the director is right, what is th

marusya05 [52]

Answer:

The probability that the proportion of books checked out in a sample of 412 books would differ from the population proportion by less than 4% is P=0.9255.

Step-by-step explanation:

The population's proportion is $\pi=0.29$