Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
Let the two ages be j and m, respectively. Then j+m>32.
Solving for Mary's age, we get m > 32 - j. Because j = m + 2, m > 32 - (m+2).
Continue solving for m: Adding m to both sides of this inequality results in
2m > 32 - 2. Then 2m > 30, and m > 15. Mary's age is greater than 15.
You apply the rule to put the exponent in front, and lower it by one. But since this is a nested expression, you apply it twice:
4*(5x^3-4)^3 * 3*5x^2 =
60x^2 (5x^3-4)^3
Answer:
Step-by-step explanation:
Given
Let
Therefore,
