Answer:
1. Find < ACB
2. Use that triangles =180 to find <B = 41
Step-by-step explanation:
1.We need to find < ACB
<ACB +<DBC= 180 They make a straight line
Subtract DBC from each side
<ACB = 180 - <DBC
We know DCB = 113
ACB = 180 -113
ACB = 67
2.The three angles of a triangle = 180, so we can then find <B
<A +<B + <ACB = 180
72 + B + 67 = 180
Combine like terms
139+ <B = 180
Subtract 139 from each side
<B = 180-139
<B =41
Okay so this is all about interior angles.
And interior angles all add up to 180.
Since 113 is an exterior, you need to find the interior of C.
180-113=67°
Interior of C is 67°
Add 67 and 72.
now, 180=B+139
Subtract 139 from 180.
Your answer should be AngleB= 41°
(4, -6), (-10, -6), (-3, 1), (-3, -13)
If we add/subtract t to/from any x/y coordinate, we will form a line segment with length 7. Hence, (4, -6), (-10, -6), (-3, 1), (-3, -13).
g=-7x-1/x