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IRISSAK [1]
3 years ago
14

If f(x)= 3x+6 which of the following is the inverse of f(x)

Mathematics
2 answers:
Lisa [10]3 years ago
4 0

Answer:

f(x)^-1 = 1/3x - 2

Step-by-step explanation:

Replace f(x) with y and solve:

y = 3x + 6

Swap x and y

x = 3y + 6

Now isolate y

x/3 = 3y/3 + 6/3

1/3 x = y + 2

1/3 x - 2 = y + 2 - 2

y = 1/3x - 2 or f(x)^-1 = 1/3x - 2

sweet-ann [11.9K]3 years ago
4 0

For this case we have the following function:

f (x) = 3x + 6

We must find the inverse of the function, then:

Replace f (x) with y:y = 3x + 6

We exchange the variables:

x = 3y + 6

We solve for "y":

Subtracting 6 on both sides of the equation:

x-6 = 3y

Dividing between 3 on both sides of the equation:

y = \frac {x} {3} - \frac {6} {3}\\y = \frac {x} {3} -2

We change y by f ^ {- 1} (x), and finally we have:

f ^ {- 1} (x) = \frac {x} {3} -2

ANswer:

f ^ {- 1} (x) = \frac {x} {3} -2

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Please help! will give brainliest !!
Veseljchak [2.6K]

Answer:

1, 2, 8, 128, 32768

Step-by-step explanation:

recursive \: formula: \\  a _{n} = 2. {( a_{n - 1} )}^{2}  \\  \\ a _{1} = 1...(given) \\  \\ a _{2} = 2. {( a_{2 - 1} )}^{2}   = 2 {(a _{1} )}^{2}  = 2 {(1)}^{2}  \\  \\  a _{2} = 2\\  \\a _{3} = 2. {( a_{3 - 1} )}^{2}   = 2 {(a _{2} )}^{2}  = 2 {(2)}^{2}  \\  \\  a _{3} = 8\\  \\a _{4} = 2. {( a_{4 - 1} )}^{2}   = 2 {(a _{3} )}^{2}  = 2 {(8)}^{2}  \\  \\  a _{4} = 128\\  \\a _{5} = 2. {( a_{5 - 1} )}^{2}   = 2 {(a _{4} )}^{2}  = 2 {(128)}^{2}  \\  \\  a _{5} = 32,768\\  \\

Thus the first five terms are: 1, 2, 8, 128, 32768.

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3 years ago
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