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2 years ago

Can Someone Please Help!!!

Mathematics

2 answers:

Brums [2.3K]2 years ago

5 0

Answer: 5 raised to the power of 4 is 625 and 3 raised to the power of 2 is 9

Step-by-step explanation:

1- 5x5x5x5= your answer (625) 5x5=25, 25 x 25 = 625

2- 3x3= your answer (9)

You then add both products, leaving you with 634.

Kobotan [32]2 years ago

3 0

Answer: 634

Step-by-step explanation: All we do is solve the exponents and then add. First we solve 5^4 which is equal to 625

5^4=625

Then we solve for 3^2 which is equal to 9

3^2=9

Finally we add.

625+9=634

And we have our answer.

<em>Hope this helps!</em>

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A number cube is rolled.what is the probability of rolling a number greater than 4

frosja888 [35]

Answer: 2/6

Step-by-step explanation:

There’s only 2 numbers greater than 4 on a die, so two would be the numerator and the denominator would be the number of possibilities you could roll, which is 1-6.

8 0

2 years ago

Read 2 more answers

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago

Find the midpoint of the line segment with the endpoints A and B.

zavuch27 [327]

Answer:

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\\$

From the question we have

$m = ( \frac{2 + 10}{2} \: , \: \frac{6 + 8}{2} ) \\ = (\frac{12}{2} \: , \: \frac{14}{2} ) \: \: \: \: \: \: \:$

We have the final answer as

Hope this helps you

3 0

2 years ago

What is an equation of the line that passes through the point (-6, -7) and is

Alexandra [31]

Answer:

Step-by-step explanation:

Product of slope of perpendicular lines = -1

6x + 5y = 30

Write this equation in y = mx + b form

5y = -6x + 30

y = $\frac{-6}{5}x+\frac{30}{5}$

$y=\frac{-6}{5}x + 6$

Slope of this line m₁ = -6/5

m₁ * m₂ = -1

m₂ = -1÷m₁ = -1 * $\frac{5}{-6}$

$m_{2}=\frac{5}{6}$ & (-6 , -7)

Equation of the required line: y - y₁ = m (x - x₁)

$y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2$

8 0

2 years ago

Solve the system by graphing

Juli2301 [7.4K]

Where is the picture?

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2 years ago