y = x^2 -4x
x = -1
y = (-1)^2 - 4×-1=1+4 = 5
x= 0
y = (0)^2 - 4×0 = 0
x = 1
y = 1^2 -4×1 = 1-4 = -3
x = 2
y = 2^2 -4×2 = 4-8 = -4
x=3
y = 3^2 - 4×3 = 9-12 = -3
x = 4
y = 4^2 - 4×4 = 16 - 16 = 0
now 2nd equation
y = 2x^2 + x
x = -2
y = 2 (-2)^2 + (-2)= 8-2 = 6
x = -1
y = 2 (-1)^2+(-1)= 2-1 = 1
x = 0
y = 2(0)^2 +0 = 0
x = 1
y = 2 (1)^2 + 1 = 3
x = 2
y = 2(2)^2+2= 8 + 2 = 10
Answer:
(5x^2-3) +(2x^2-3x^3)
=3x^3+5x^2+2x^2-3
= 3x^3 +7x^2 -3
Step-by-step explanation:
hope this is correct cuz I'm not an expert...
Answer:
6x+4
Step-by-step explanation:
First thing to do is distribute 1/4 into the parenthesis. So 1/4 times 8x and 16. Which will give you 2x and 4. Then add like terms which will be 2x + 4x which is 6x. Then you have the 4 left over so your new equation is 6x+4.
Graph the trigonometric function using the amplitude,period,phase shift and vertical shift.
Vertical Asymptotes:x=pi/6 =pi n/2 where n is an integer
Amplitude is none
period is pi/2
phase shift is pi/6 to the right
vertical shift is 0