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Flura [38]
4 years ago
7

A spinner has four unequal parts. Tony spun the spinner 16 times. The spinner landed on

Mathematics
1 answer:
gogolik [260]4 years ago
7 0

Answer:Green

Step-by-step explanation:

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The answer should be gallons per minute
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The ratio of male to female spectators at ice hockey games is 4:5. At the Steelers' last match,4500 men watched the match. What
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Read 2 more answers
11. Keng creates a painting on a rectangular canvas with a width that is four inches longer
GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

We multiply the length and height to get the area

area = (length)*(height)

area = (h+4)*(h)

area = h(h+4)

area = h^2 + 4h .... apply the distributive property

The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

area = h( x ) + 10( x )

area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

The units for the area are in square inches.

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3 years ago
Graph a line that contains the point (3,-6) and has a slope of -1/2
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4 0
3 years ago
What is the component form of the vector represented by 2a when a⃗ =〈−2,3〉?
Paladinen [302]

Answer:

\vec v = 2\cdot \vec a = \langle -4,6 \rangle

Step-by-step explanation:

Let \vec a = \langle -2, 3 \rangle, we need to determine \vec v = 2\cdot \vec a, which can be found by applying the following property:

\alpha \cdot \langle x,y \rangle = \langle \alpha \cdot x, \alpha \cdot y\rangle, \forall \,\alpha,x,y\in \mathbb{R} (1)

Then,

\vec v = 2\cdot \langle -2,3 \rangle

\vec v = \langle -4,6 \rangle

8 0
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