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Solnce55 [7]
3 years ago
14

*order of operation 296-(65•2-32/4

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

174

Step-by-step explanation:

start with the numbers inside the parenthesis! next, multiply (65 x 2) = 130, then divide (32/4) = 8. then, subtract 130-8 to get 127. now move outside the parenthesis and subtract 296-127 = 174!

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Sara takes 1/6 of an hour to vacuum his moms car it takes 4 times that long to wash the car then it takes you to wax the car twi
Nataly [62]
<h2>Answer:</h2><h2>2 hours & 10 minutes </h2><h2>Step-by-step explanation:</h2><h2>1/6 of an hour is 10 minutes. She vacuumed for 10 minutes. It took 4 times as long to wash the car so 10 * 4 = 40. She washed the car for 40 minutes. It took her twice as long to wax the car as it did for her to wash it so 40 * 2 = 80. She waxed the car for 80 minutes. 10 + 40 + 80 = 130 minutes or 2 hours and 10 minutes. </h2>
3 0
3 years ago
Help me out please???
xenn [34]

Answer:

(x,y) => (x+3, y+4)

Step-by-step explanation:

Given a triangle DEF, D(4,2), E(3,3), F(2,1).

Centroid of the area (and the vertices) equals the mean of the coordinates, namely ( (4+3+2)/3, (2+3+1)/3 ) = (3,2)

To translate (3,2) to (6,6), we need the rule

(x,y) => x+(6-3), y+(6-2), or

(x,y) => (x+3, y+4)

5 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe
algol [13]
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)
6 0
3 years ago
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The circumference of a circle is 18.84 inches. what is the circle's radius
vivado [14]

Answer:

Circumference : 18.84 inches

Radius: 3 inches

6 0
3 years ago
50 PTS ANSWER ALL &lt;3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
3 years ago
Read 2 more answers
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