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2 years ago

5

A football is kicked vertically upward from a height of 4 feet with an initial speed of 65 feet per second. The formula h=4+65t−

16t2 describes the ball's height above the ground, h, in feet, t seconds after it was kicked. Use this formula to find the ball's height 2 seconds after it was kicked. The ball's height, 2 seconds after it was kicked, was nothing feet. I NEED EXTREME HELP PLEASE !!!

2 answers:

KATRIN_1 [288]2 years ago

3 0

Answer: h = 70ft

Step-by-step explanation: To find the height the ball reached after 2 seconds, substitute variable t for 2 and calculate height:

$h=4+65t-16t^{2}$

$h=4+65.2-16.2^{2}$

$h=4+65.2-16.4$

$h=4+130-64$

h = 70

<u>After 2s, the football reached a height of </u><u>70 feet</u><u>.</u>

Sedaia [141]2 years ago

3 0

Answer:

if its for 3 seconds the answer is 55

Step-by-step explanation:

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2 years ago

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2 years ago

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Can you please help me?

Musya8 [376]

Answer:

Option (a)

Step-by-step explanation:

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

Slope (m) = $\frac{y_2-y_1}{x_2-x_1}$

Slope of the line passing through (-4, 3) and (6, 3) will be,

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6 0

2 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is </u></em>

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

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2 years ago

What is the distance from point (– 1, 3) to the line 3x – 4y = 10?

natta225 [31]

Answer:

5 units

Step-by-step explanation:

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d = $\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }$

For the point (- 1, 3 ) , with m = - 1 and n = 3

3x - 4y = 10 ( subtract 10 from both sides )

3x - 4y - 10 = 0

with A = 3 , B = - 4 , C = - 10

d = $\frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }$

= $\frac{|-3-12-10|}{9+16}$

= $\frac{|-25|}{\sqrt{25} }$

= $\frac{25}{5}$

= 5

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1 year ago