Question

A football is kicked vertically upward from a height of 4 feet with an initial speed of 65 feet per second. The formula h=4+65t−16t2 describes the​ ball's height above the​ ground, h, in​ feet, t seconds after it was kicked. Use this formula to find the​ ball's height 2 seconds after it was kicked. The​ ball's height, 2 seconds after it was​ kicked, was nothing feet. I NEED EXTREME HELP PLEASE !!!

Answer 1

Answer: h = 70ft

Step-by-step explanation: To find the height the ball reached after 2 seconds, substitute variable t for 2 and calculate height:

$h=4+65t-16t^{2}$

$h=4+65.2-16.2^{2}$

$h=4+65.2-16.4$

$h=4+130-64$

h = 70

After 2s, the football reached a height of 70 feet.

Answer 2

Answer:

if its for 3 seconds the answer is 55

Step-by-step explanation: