Answer:
7 roses
Step-by-step explanation:
16-9=7
-4 x 9= -36 and the when you add 5 to -36 you get -31. Hope this helps
1) Change radical forms to fractional exponents using the rule:The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>
![\sqrt[n]{3} = 3^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B3%7D%20%3D%20%20%203%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D)
.
The square root of 3 (

) = 3 to the one-half power (

).
The 5th root of 3 (
![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
) = 3 to the one-fifth power (

).
2) Now use the product of powers exponent rule to simplify:This rule says

. When two expressions with the same base (a, in this example) are multiplied, you
can add their exponents while keeping the same base.
You now have

. These two expressions have the same base, 3. That means you can add their exponents:
3) You can leave it in the form
or change it back into a radical ![\sqrt[10]{3^7}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B3%5E7%7D%20)
------
Answer:
or
So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

Now that we've factored our equation, we can use ZPP and break it up:

So, our solutions are:

Answer:
c im pretty sure
Step-by-step explanation: