Answer:
Option D
Step-by-step explanation:
A type I error occurs when you reject the null hypothesis when it is actually true.
The null hypothesis in this case is minimum breaking strength is less than or equal to 0.5.
A type one error would be allowing the production process to continue when the true breaking strength is below specifications.
We are not given tables, so will just use the amortization formula.

where
P=amount to be deposited today, to be found
A=amount withdrawn each year=18000
i=Annual interest=9%
n=number of years = 20
Substituting values,

=164313.82 to the nearest cent
PEMDAS
(3+2)=5
(5-1+2)=6
6*5*4=120
Answer:
n = (177-45)/2
hope this helps! If so I would really appreciate brainliest
Answer:
V≈268.08cm³
Step-by-step explanation: