Answer:
x=52 m1= 40 m2= 140
Step-by-step explanation:
x-12+x+88=180 since they are linear pair
2x+76=180 collect like terms
2x=180-76
2×÷2=104÷2
×=52
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Answer:
g(x) = 0.5x²
Step-by-step explanation:
Since the graph of g(x) still passes through the origin and is u shaped, it is also a quadratic graph but with a different coefficient of x².
Let g(x) = ax²
When x=2, g(x) = 1
Hence, 2a = 1
a = 0.5
Therefore, <u>g(x) = 0.5x²</u>
Juan's least integer scores in both tests will be 85 and 100 respectively.
- Test average of his two scores is atleast 92
Let :
- Score on test 1 = b
- Score on test 2 = b + 15
Average score can be related thus:
- (Sum of score ÷ number of test) ≥ 92
- (b + b + 15) ÷ 2 ≥ 92
- (2b + 15) ÷ 2 = 92
- 2b + 15 = 184
- 2b = 184 - 15
- 2b = 169
- b = 169 ÷ 2
- b = 84.5
Therefore, since both scores are integers, his least scores on both tests will be ::
Learn more :brainly.com/question/15528814
Answer:
a) C. No, a carton can have a puncture and a smashed corner.
b) The probability that a carton has a puncture or a smashed corner is P(X ∪ Y) = 0.104.
Step-by-step explanation:
To be mutually exclusive, the probability of the two events happening at the same time should be 0. But the probability that a carton has a puncture and has a smashed corner is 0.004 and not 0.
Then, we can conclude the events "selecting a carton with a puncture" and "selecting a carton with a smashed corner" are not mutually exclusive.
The answer is "C. No, a carton can have a puncture and a smashed corner."
We can calculate the probability that the carton has a puncture <em>or </em>has a smashed comer simply by adding the probability of each event:

P(X ∪ Y): probability that a carton has a puncture or a smashed corner.