Answer:3
b
−
2
c−
d
,
t
o
3
,
3
+
3d
−
3
b
Step-by-step explanation:
(
b
−
c
)
⋅
3
+
(
c
-d
) raise t
o 3
3
+
(
d
−
b
)
⋅
3
Write the problem as a mathematical expression.
(
b
−
c
)
⋅
3
+(
c
−
d
) raise t
o3
3+
(
d
−
b)
⋅
3
Remove parentheses.
(
b
−
c)
⋅
3
+
c
−
d
,
t
o
3
,
3
+
(
d
−
b
)
⋅
3
Simplify each term.
Apply the distributive property.
b
⋅
3
−
c
⋅
3
+
c−
d
Move 3 to the left of b
.
3
⋅
b
−
c
⋅
3
+
c
−
d
Multiply 3 by −
1 ⋅
3
b
−
3
c
+
c
−
d
Add −
3
c and c.
3
b
−
2
c
−
d
,
t
o
3
,
3
+
(
d
−
b
)
⋅
3
Simplify each term.
Apply the distributive property.
3
+
d ⋅
3
−
b ⋅
3
Move 3 to the left of d
.
3
+
3
⋅
d
−
b
⋅
3
Multiply 3 by −
1
.
3
+
3
d
−
3
b
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
|96.55−0.02|= x
|96.55+0.02|=x
Step-by-step explanation:
Given that:
Measured length of beam = 96.55 cm
Measurement accuracy = plus or minus (± 0.02cm)
Limits of actual length of the beam:
Let limit of actual length = x
Lower limit :
|measured length - accuracy| = x
|96.55 - 0.02| = x
96.53) x
Upper limit :
|measured length + accuracy| = x
|96.55 + 0.02| = x
96.57 = x
H is hours
9.20H ≧ 299
H ≧ 299/9.20
H ≧ 32.5
Hours to work at summer job to pay $299 is 32 hours and 30 minutes.
