To solve the given equation, you would need to multiply t by both terms inside the parenthesis.
The equation would be D. (t*14) - (t*5)
Use photo math or Socratic
4 = 7 - 3
1 = 4 - 3
-2 = 1 - 3
-5 = -2 - 3
=> An = A (n-1) - 3, where A1 = 7
The next term is A6 = A5 - 3 = - 5 - 3 = - 8
So the answer is the fourth option.
Step #1 for both: figure out which interval your x-value fits into.
For f(-2), x=-2 and -2 fits with x ≤ -2, the top interval.
For f(3), x=3 and 3 fits into -2 < x ≤ 3, the middle interval.
Step #2 for both, plug in your x-value to the piece of the function that fits with that interval.
For f(-2), we know x≤-2, so we use 2x+8 to evaluate x=-2.
For f(3), we know -2
f(-2) = 2(-2)+8 = -4+8 = 4
f(3) = (3)^2 -3 = 9-3 = 6
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