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zmey [24]
3 years ago
11

15 points!

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

Hi there! You are provided with two points, this is all you need to calculate the line's slope.


The equation for slope is:

\frac{y2 - y1}{x2 - x1}

\frac{10 - 8}{3 - 7} = -\frac{2}{4}

Slope: -2/4


Point slope form, or y-y1 = m(x - x1). All we have to do is take the x and y coordinates of either point, as well as the slope, and plug them into the equation.

y - 10 = -2/4(x - 3)


Write the equation in slope-intercept form (y=mx+b)

y - 10 = -2/4(x-3)\\y = -2/4(x-3) + 10\\y = -2/4x + 1.5 + 10\\y = -2/4x + 11.5


A) -2/4

B) y - 10 = -2/4(x - 3)

C) y = -2/4x + 11.5

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Lyrx [107]
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
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</span>
b.)
<span>s = ut + 1/2 a t^2
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\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
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Answer:

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Step-by-step explanation:

The graph of these equations is attached. The solution is ...

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