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zmey [24]
3 years ago
11

15 points!

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

Hi there! You are provided with two points, this is all you need to calculate the line's slope.


The equation for slope is:

\frac{y2 - y1}{x2 - x1}

\frac{10 - 8}{3 - 7} = -\frac{2}{4}

Slope: -2/4


Point slope form, or y-y1 = m(x - x1). All we have to do is take the x and y coordinates of either point, as well as the slope, and plug them into the equation.

y - 10 = -2/4(x - 3)


Write the equation in slope-intercept form (y=mx+b)

y - 10 = -2/4(x-3)\\y = -2/4(x-3) + 10\\y = -2/4x + 1.5 + 10\\y = -2/4x + 11.5


A) -2/4

B) y - 10 = -2/4(x - 3)

C) y = -2/4x + 11.5

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Neither, for lines to be parallel they have to have the same slope, and for lines to be perpendicular they have to be the negative reciprocal of the slope of the other line. In this case, the line perpendicular to the line with slope m=10 would be m=1/-10 or -1/10

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