Answer:
10000 options
Step-by-step explanation:
There are 10 options of digit from 0 to 9. It means there are 10 options for the first slot, 10 for the 2nd slot, 10 for the 3rd slot, and 10 for the last slot of each of the 4 slots of the password. For all 4 passwords the total amount of choices would be

The only numbers I could think of would be 1, 2, and 4 because 4 is greater than 3 (2+1) and four times greater than 1 (2-1)
For the two parallelogram to be congruent, their corresponding sides must be equal
<h3>
Congruent figures</h3>
Two figures are said to be congruent if they are of the same shape and their corresponding sides and angles are congruent to each other. The SSS congruency theorem states that two figures are congruent of all their sides are congruent.
For the two parallelogram to be congruent, their corresponding sides must be equal
Find out more on similar figures at: brainly.com/question/26173060
Answer:

Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner
is:

where :
(a and b are the length and the breath of the rectangle respectively )


![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)

Thus; the moment of inertia of the lamina about one corner is 
Answer:
7³
Step-by-step explanation:
Using PEMDAS, we see that E (which stands for exponents) comes before M (which stands for multiplication) and A (which stands for addition) so the first operation you should do is 7³.