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Phoenix [80]
3 years ago
13

What is 400+70+8 written in standard form?

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

478

Step-by-step explanation:

478

4=400

7=70

8=8

you have to count the zeros

noname [10]3 years ago
3 0
<h3>Answer: C) 478</h3>

400 = four hundred

70 = seventy

8 = eight

Read the words on each right hand side, and read straight down to get "four hundred seventy eight" which is written as 478.

It might help to line up the terms like you see in the image below

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Read 2 more answers
Find two positive consecutive odd integers such that square of the smaller integer is 10 more than the larger integer
Otrada [13]

Let 2n+1 be the smaller integer. The larger integer is then 2n+3, and we have

(2n+1)^2=10+(2n+3)\implies4n^2+4n+1=2n+13

\implies4n^2+2n-12=0

\implies2n^2+n-6=0

\implies(2n-3)(n+2)=0

\implies 2n-3=0\text{ or }n+2=0

\implies n=\dfrac32\text{ or }n=-2

We omit n=-2, since 2(-2)+1=-3 is negative.

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There are no consecutive odd integers that satisfy the given condition!

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