All categories

3 years ago

Any one know the answer it has to be turned in tomorrow morning

Mathematics

2 answers:

AVprozaik [17]3 years ago

8 0

For Question 16 you need to make the lowest number using 1, 2,3,4,5,6,7,8,9. Therefore, with each number in order of lowest to highest it is 123,456,789. for Q 17, 900 is missing. When you add the values 3,000+40+7 you get 3,047. Subtract that from 3,947, (3,947-3,047) and you get 900.

Veseljchak [2.6K]3 years ago

6 0

17: 900 because 3,000 + 900 + 40 +7 is 3,947 or 3,947-3,000-40-7= 900

You might be interested in

Math question on big ideas math the 1/3 confuses me I hate fractions

jok3333 [9.3K]

a simple way to do away with denominators, is we can simply multiply both sides by the LCD, in this case the LCD is 3, so let's multiply both sides by 3.

$\bf 3\left( \cfrac{1}{3}x+y \right)=3(4)\implies x+3y=12\implies 3y=12-x
\\\\\\
y=\cfrac{12-x}{3}\implies \stackrel{\textit{distributing the denominator}}{y=\cfrac{12}{3}-\cfrac{x}{3}}\implies y=4-\cfrac{1}{3}x$

6 0

3 years ago

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago

Someone please help thanks!!!

MArishka [77]

Answer:

-3/2

Step-by-step explanation:

The slope of a line is calculated by dividing the difference in the y-coordinates by the difference in the x-coordinates.

Here, the given ordered pairs are (-6, -8) and (-14, 4), so the slope is:

slope = m = (4 - (-8)) / (-14 - (-6)) = 12 / (-8) = -3/2

The answer is thus -3/2.

~ an aesthetics lover

3 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form of the line that bisects the angle formed by BA and BC

slega [8]

Given:

Angled formed by ray BA and ray BC is 90 degrees.

To find:

The equation of line that bisects the angle formed by ray BA and ray BC.

Solution:

If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.

It is possible if the line passes though point B(-1,3) and other point (-2,4).

Equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$