Question

A photographer will arrange 6 people of 6 different heights for a photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?

Answer 1

Answer:5

Step-by-step explanation:

This can be solved by fixing the position of shortest and tallest person in the first and second row respectively .

Rest we have four person remaining and we have to arrange 4 person in 4 positions therefore we can do it in

$^4P_2$ways out of which we have to exclude the case when both the tall persons is in the first row and short person in second rows

Therefore a total of 6-1 ways is possible