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Sloan [31]
4 years ago
5

A photographer will arrange 6 people of 6 different heights for a photograph by placing them in two rows of three so that each p

erson in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?
Mathematics
1 answer:
Svetllana [295]4 years ago
3 0

Answer:5

Step-by-step explanation:

This can be solved by fixing the position of shortest and tallest person in the first and second row respectively .

Rest we have four person remaining and we have to arrange 4 person in 4 positions therefore we can do it in

^4P_2ways out of which we have to exclude the case when both the tall persons is in the first row and short person in second rows

Therefore a total of 6-1 ways is possible

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Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.2 chocolate chips per cookie and a sta
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Answer:

Percentile 5

z=-1.64

And if we solve for a we got

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Step-by-step explanation:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

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Where \mu=24.2 and \sigma=2.6

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Percentile 5

For this part we want to find a value a, such that we satisfy this condition:

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P(X   (b)

We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05

Using this condition we got:

P(X  

P(z

Replacing we got:

z=-1.64

And if we solve for a we got

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