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Serggg [28]
3 years ago
11

Which of the following is equivalent to 3(y - 1+ 2y)?

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

3) 9y-3

Step-by-step explanation:

3 (y - 1 + 2y)

3×y - 3×1 + 3×2y

3y - 3 + 6y

rearranging like terms together:

3y + 6y - 3

9y - 3

vodomira [7]3 years ago
4 0

Answer:

3, 9y-3

Step-by-step explanation:

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What triangle can be obtuse?
True [87]

Answer:

Isosceles and scalene triangles can both be obtuse.

3 0
3 years ago
The Marked price of a jacket at a dealer's shop is 2400. The dealer allows a discount of 15% to the retailer. As the company's p
Andrej [43]

Answer:

2400

2640

360

Step-by-step explanation:

the retailer has to sell it for the same price as the dealer.

so, both mark it for 2400 sale price.

if a customer buys it at the retailer, the retailer makes the 15% discount he got from the dealer as profit.

2400 = 100%

1% = 2400/100 = 24

15% = 24×15 = 360

the retailer makes this profit no matter what other fees or taxes are added.

the final price is then including 10% VAT

2400 = 100%

10% = 24×10 = 240

final price = SP + VAT = 2400 + 240 = 2640

6 0
2 years ago
Find g (a + 1 ), if g(x)=5x-3 ​
nordsb [41]

Answer:

g(a+1)=5a+2

Step-by-step explanation:

so (a+1) is the value of x

you can write it like this:

x=a+1

using substitution, we can swap out all 'x's for 'a+1's. like so;

g(a+1)=5(a+1)-3  -- given

        =5a+5-3   --  distribute

        =5a+2      --  simplify!

Hope i helped! have a great day! please mark brainliest!!

5 0
3 years ago
What are the solutions to the following system of equations? y=x^2+12x+30 and 8x-y=10
Ierofanga [76]
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side.  To do this, add -8x+10 to both sides.  Then 0 = x^2 +4x +40.  You must now solve this quadratic equation for x, if possible.  I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10  and  x^2+12x+30 on the same screen.  You will see two separate graphs that do NOT intersect.  This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
6 0
3 years ago
2.1 & 2.2 Assessment: Vertex & Standard Form of Quadratic Functions
Brums [2.3K]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2 - 9\qquad \textit{we also know that} \begin{cases} x=2\\ y=-7 \end{cases} \\\\\\ -7=a(2-1)^2-9\implies 2=a(1)^2\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} y=2(x-1)^2 -9 \end{array}} ~\hfill

6 0
11 months ago
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