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3 years ago

Which of the following is equivalent to 3(y - 1+ 2y)?

Mathematics

2 answers:

Whitepunk [10]3 years ago

8 0

Answer:

3) 9y-3

Step-by-step explanation:

3 (y - 1 + 2y)

3×y - 3×1 + 3×2y

3y - 3 + 6y

rearranging like terms together:

3y + 6y - 3

9y - 3

vodomira [7]3 years ago

4 0

Answer:

3, 9y-3

Step-by-step explanation:

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2(csc^2 theta -cot^2 theta)

vodka [1.7K]

Answer:

Step-by-step explanation:

the answer is 12

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4 years ago

What situation should be used to rewrite 16(x^3+1)^2 -22(x^3+1)-3=0 as a quadratic equation

Oliga [24]

$16(x^3+1)^2-22(x^3+1)-3=0$

Use substitution: $x^3+1=t$

$16t^2-22t-3=0\\\\16t^2-24t+2t-3=0\\\\8t(2t-3)+1(2t-3)=0\\\\(2t-3)(8t+1)=0\iff2t-3=0\ \vee\ 8t+1=0$

$2t-3=0\ \ \ |+3\\\\2t=3\ \ \ |:2\\\\t=\dfrac{3}{2}\\..............................\\8t+1=0\ \ \ \ |-1\\\\8t=-1\ \ \ \ |:8\\\\t=-\dfrac{1}{8}$

we're going back to substitution:

$x^3+1=\dfrac{3}{2}\ \vee\ x^3+1=-\dfrac{1}{8}\ \ \ \ |subtract\ 1\ from\ both\ sides\ of\ the\ equations\\\\x^3=\dfrac{1}{2}\ \vee\ x^3=-\dfrac{9}{8}\\\\x=\sqrt[3]{\dfrac{1}{2}}\ \vee\ x=\sqrt[3]{-\dfrac{9}{8}}$

$x=\dfrac{1}{\sqrt[3]2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}\\\\\boxed{x=\dfrac{\sqrt[3]4}{2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}}$

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3 years ago

Write an equation of the line that passes through the given point and has the given slope.

n200080 [17]

Answer:

The answer to your question is y = -2x - 2

Step-by-step explanation:

Data

Point = (-4, 6)

slope = m = -2

Process

1.- Substitute the values in the formula point-slope

y - y1 = m(x - x1)

y - 6 = -2(x + 4)

2.- Simplify

y - 6 = -2x - 8

y = -2x - 8 + 6

3.- Result

y = -2x - 2 slope = -2

y-coordinate = -2

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4 years ago

What is 5 divided by 3/7

DENIUS [597]

it would be 35/3 or 11 2/3

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3 years ago

Simplify. square root 60a^3

vfiekz [6]

Answer:

2root of 15

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers