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3 years ago

What is 40 kilometers per hour in meters per hour

Mathematics

2 answers:

dexar [7]3 years ago

8 0

40 km - meters is 40 * 1000 whch is 40000 meters per hour

Pie3 years ago

6 0

1 kilometer= 1000 meters
1000*40
=40000 meters

Hope this helps!
-Benjamin

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An airplane travels 360 miles in 2 hours. At the rate, how far can the airplane travel in 8 hours. Please help me!

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Answer:

1440 miles

Step-by-step explanation:

360 miles = 2 hours

360/2=180 miles = 1 hours

8 hours = 180*80=1440 miles

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Brinlyn increased the amount of water she drank per day from 32 oz to 40 oz. By what percentage did Brinlyn increase the amount

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20%

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rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a

SpyIntel [72]

Answer:

The point O can be (x,y) or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

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Then a reflection across the y-axis has taken place.

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Then a translation a units to the right and b units up has taken place.

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(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

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Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

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3 years ago

Consider the function g(x) = 10/x

ss7ja [257]

The correct answers are:
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

Explanation:
(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = $\frac{10}{x}$ 

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = $\frac{10}{x}$ 

We can write it as:

g(x) = $\frac{10 * x^0}{x^1}$ 

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0

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