Find the area of each face and add them all together, or since a cube has 6 faces, you can multiply the area of one face by 6.
Above the graph
look at them
7x-y <span><</span>3
x-y<span><</span>4
2x-9y>2
4x+7y>3
dashed boundary line means it does't include htat means taat the symbol is < or >
cross out first 2
one way is to graph the lines as equations and shade accordingly
2x-9y>2
y<2/9x+2/9
shade on bottom
4x+7y>3
y>-7/4x+3/9
shade on top
aswer is 4x+7y>3
Answer:
The answer is 17.6
Step-by-step explanation:
Multiply 8 x 2.2, and act as if you are cutting off the left "triangle" and simply moving it to the other side, making it act like a rectangle.
Divide 4 on both sides, x=6.4/4 which is 1.6
Answer:
the area of the curve y= f(x) = x between x = 5 and x = 10
Step-by-step explanation:
- Finding the area of the curve y = f(x) = x between x = 5 and x = 10
Using the Area formula
As the area of curve lies between x = 5 and x = 10
so
so the integral expression becomes
![A=\left[\frac{x^{1+1}}{1+1}\right]^{10}_5](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cfrac%7Bx%5E%7B1%2B1%7D%7D%7B1%2B1%7D%5Cright%5D%5E%7B10%7D_5)
![=\left[\frac{x^2}{2}\right]^{10}_5](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cright%5D%5E%7B10%7D_5)
![=\frac{1}{2}\left[10^2-5^2\right]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Cleft%5B10%5E2-5%5E2%5Cright%5D)
Therefore, area of the curve y= f(x) = x between x = 5 and x = 10
