What sport do 7th graders prefer to play after school

A student’s work to simplify and combine radicals is shown below. Select the statement which best applies to the sample mathemat

jeka94

Your answer is incorrect. You forgot to get the square root of 25 and 4. Answer should be 16√2

we can only subtract radicals that are the same. At first glance, 4√50 - 2√8 are not the same, so they are not likely to be subtracted. However, each radical can still be simplified.

4 √50 = 4 √25 * 2 = 4 * 5 √2 = 20 √2
2 √8 = 2 √4 * 2 = 2 * 2 √2 = 4 √2

Now that the radicals are the same. then you can subtract the numbers.

20 √2 - 4 √2 = 16√2

4 0

2 years ago

Show all work please!!!!!!

sergij07 [2.7K]

The midpoint formula is:
(point1 + point2)/2

1) (-2 + 12)/2 = 5

2) (-1 +5)/2 = 2
    (0+2)/2 = 1
     (2,1)

3) Sqrt of (x2-x1)^2 + (y2 - y1)^2
     sqrt of (7 -1)^2 + (-7 - 1)^2
     sqrt of (6)^2 + (-8)^2
     sqrt of 36 + 64
     sqrt of 100
     10

Hope this helps!

7 0

2 years ago

The average student loan debt for college graduates is $25,150.

Aleks04 [339]

Using the normal distribution, it is found that:

a) $X \approx N(25150, 12050)$

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 25150, \sigma = 12050$ .

Hence the distribution of X can be described as follows:

$X \approx N(25150, 12050)$

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{33950 - 25150}{12050}$

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14200 - 25150}{12050}$

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

$Z = \frac{X - \mu}{\sigma}$

$-0.127 = \frac{X - 25150}{12050}$

X - 25150 = -0.127(12050)

X = $23,519.65.

$Z = \frac{X - \mu}{\sigma}$

$0.127 = \frac{X - 25150}{12050}$

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0

1 year ago

Answer the following questions about the standard normal random variable Z. (Use 4 decimal places in your answers to parts a. th

Mashcka [7]

Answer:

a) 0.6636

b) 0.0951

c) 0,9474

d) 0.0047

e) 0.9957

f) 0.1308

Step-by-step explanation:

We look in tables z values and then we see carefully aereas inside normal curve

a) P[- 1.46 < z < 0.63 ] point 1.46 from table 0.0721 this s th area from value -1.46 to the left . And the value z = 0.63 corresond to the area 0.7357 which includes the area between 1.46 to the left tail, then we have to subtarct and get 0.6636 .

P[- 1.46 < z < 0.63 ] = 0.6636 66.36 %

b) P [ 0 < z < 1.31 ] we just need the area for point 1.31 that is 0.0951

P [ 0 < z < 1.31 ] = 0.0951 9.51 %

c) P [z > - 1.62 ] = 1 - 0.0526

P [z > - 1.62 ] = 0,9474 94.74 %

d) P[z < - 2.6 ] = 0.0047 0.47 %

e) P [ z < 2.63 ] = 1 - 0.0043

P [ z < 2.63 ] = 0.9957 99.57 %

f) P [ -2.58 < z < -1.1 ] = 0.1357 - 0.0049 =

P [ -2.58 < z < -1.1 ] = 0.1308 13.08 %

3 0

3 years ago

A car is traveling at a speed of 60 kilometers per hour. what is the car's speed in miles per hour? how many miles will the car

PilotLPTM [1.2K]

60km/1.6 = 37.5mph

It will travel 3(37.5) = 112.5 miles.

5 0

2 years ago

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What sport do 7th graders prefer to play after school ​

What sport do 7th graders prefer to play after school