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Anarel [89]
3 years ago
7

What sport do 7th graders prefer to play after school ​

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0
Basketball is the most played after school
stich3 [128]3 years ago
4 0
Basketball was voted hugest
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SH<br>What is the greatest common factor (GCF) of 35 and 28?<br>​
Brilliant_brown [7]

Answer: 7

Step-by-step explanation:

We found the factors and prime factorization of 28 and 35. The biggest common factor number is the GCF number. So the greatest common factor 28 and 35 is 7.

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Write this equation in standard form y=3x+10
Roman55 [17]

Answer:

to standard form

3x-y = -10

6 0
3 years ago
Ramon drew boxplots to summarize the number of pages in each chapter of two books. The value of the interquartile ranges of thes
Brut [27]

Answer:

The answer is c

Step-by-step explanation:

The middle line is in the same spot

7 0
3 years ago
Tammy has a job that has a weekly salary of $1,200 but wants to switch a job that has a monthly salary of $11,700. How much more
iogann1982 [59]

Answer:

$1529.8

Step-by-step explanation:

Given:

Tammy has a job that has a weekly salary of $1,200.

But wants to switch a job that has a monthly salary of $11,700

Question asked:

How much more will she make per week if she switch to the new job?

Solution:

Monthly salary of a new job, she wants to switch = $11,700

Weekly salary  of a new job, she wants to switch = ?

As we know : 1 month = 4.286 Weeks

Salary of 1 month for a new job, she wants to switch = $11,700

Salary of  4.286 Weeks  for a new job, she wants to switch =  $11,700

Salary of 1 Week  for a new job, she wants to switch = 11700\div4.286=\$2729.81

Now, we have to find that How much more she will make per week,  if she switch to the new job.

More money she will make for a new job she wants o switch = Weekly salary for a new job, she wants to switch  - Weekly salary of current job

More money she will make, for a new job = $2729.8 - $1200 = $1529.8

Therefore, she will  make $1529.8 more  per week if she switch to the new job.

3 0
3 years ago
The owner of Matt’s Gas Station wants to study gasoline purchases of customers at his station. In 2017, the mean amount of gas
gulaghasi [49]

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 9

For the alternative hypothesis,

µ ≠ 9

This is a 2 tailed test

Since the population standard deviation is given, z score would be determined from the normal distribution table. The formula is

z = (x - µ)/(σ/√n)

Where

x = sample mean

µ = population mean

σ = population standard deviation

n = number of samples

From the information given,

µ = 9

x = 9.9

σ = 2.5

n = 50

z = (9.9 - 9)/(2.5/√50) = 2.55

Looking at the normal distribution table, the probability corresponding to the area above the z score is 1 - 0.99461 = 0.00539

Recall, population mean is 9

The difference between sample sample mean and population mean is 9.9 - 9 = 0.9

Since the curve is symmetrical and it is a two tailed test, the x value for the left tail is 9 - 0.9 = 8.1

the x value for the right tail is 9 + 0.9 = 9.9

These means are higher and lower than the null mean. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area. We already got the area above the z score as z = 0.00539

We would double this area to include the area in the left tail of z = - 2.55. Thus

p = 0.00539 × 2 = 0.01078

Since alpha, 0.01 < 0.01078, we would reject the null hypothesis

But we are told to use the critical value approach, then

Since α = 0.01, the critical value is determined from the normal distribution table.

For the left, α/2 = 0.01/2 = 0.005

The z score for an area to the left of 0.005 is - 2.575

For the right, α/2 = 1 - 0.005 = 0.995

The z score for an area to the right of 0.995 is 2.575

In order to reject the null hypothesis, the test statistic must be smaller than - 2.575 or greater than 2.575

Since - 2.55 > - 2.575 and 2.55 < 2.575, we would reject the null hypothesis. This corresponds to our previous decision.

b) we would assume normal distribution because the sample size is sufficiently large and the population standard deviation is known.

c) Confidence interval is written in the form,

(Sample mean ± margin of error)

Since the sample size is large and the population standard deviation is known, we would use the following formula and determine the z score from the normal distribution table.

Margin of error = z × σ/√n

The z score for confidence level of 99% is 2.58

Margin of error = 2.58 × 2.5/√50 = 0.91

Confidence interval = 9.9 ± 0.91

The lower end of the confidence interval is

9.9 - 0.91 = 8.99

Therefore, p = 9 will be contained in the interval.

4 0
3 years ago
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