Ask question

Ask question

All categories

4 years ago

7

What sport do 7th graders prefer to play after school

2 answers:

SCORPION-xisa [38]4 years ago

7 0

Basketball is the most played after school

stich3 [128]4 years ago

4 0

Basketball was voted hugest

You might be interested in

Is xy = yx? Explain how you know

blagie [28]

Answer:

Yes

Step-by-step explanation:

xy=yx because either way, you would end with the same product. For example, if x was 3 and y was 2, you would have (3)(2)=(2)(3), giving you 6=6 which is, in fact, a true statement.

4 0

3 years ago

If a=-1,b=-6 and c=2 then what is the value of b2-4ac?

grandymaker [24]

Answer:

-4

Step-by-step explanation:

(-6)(2)-4(-1)(2)

(-12)-(-8)

-12+8=-4

4 0

3 years ago

Fill in the blank.

gavmur [86]

Answer:

297 cubic centimeters

Step-by-step explanation:

volume is LWH

11*9*3 = 297

6 0

3 years ago

Graph the equation y = x2 + 8x + 12 on the accompanying set of axes. You must

UkoKoshka [18]

Answer:

Step-by-step explanation:

Roots: set y = x^2 + 8x + 12 = 0 and solve for x: x + 6 = 0, so x = -6 is one root. The other is x = -2. The corresponding points are (-6, 0) and (-2, 0).

y-intercept: Let x = 0. Then y = 12. The y-intercept is (0, 12).

Axis of symmetry: x = -b / (2a) => x = -8/(2*1) = -4: x = -4

Vertex y-value: evaluate y at x = - 4: (-4)^2 + 8(-4) + 12 = -4: (-4, -4)

Arbitrarily chosen x value: x = 1 => 1^2 + 8(1) + 12 = 21: (1, 21)

The five points are: (-6, 0) and (-2, 0), (0, 12), (-4, -4), (1, 21). The vertex is (-4, -4). The parabolic graph opens UP.

8 0

3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

3 years ago