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2 years ago

15

Joey has a beach ball with a radius of 20 cm what's the volume of air will it hold when fully infflated

1 answer:

zysi [14]2 years ago

3 0

volume of sphere = V=(4/3)(pi)r^3

so V = (4/3) x 3.14 x 20^3 = 33,493.33 cubic cm

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I need help I will give BRAINLEST

GREYUIT [131]

Answer:

25%

Step-by-step explanation:

To solve this, we can use the percent change formula shown in the picture attached below. $x_{2}$ is the new value, $x_{1}$ is the old value, and $C$ represents the change. For this problem, 80 is the new value and 64 is the old value. Let's plug those numbers into the formula and solve for the percent change:

$C = \frac{(80-64)}{64} \\$ × $100$

$C = \frac{16}{64}$ × $100$

$C = 0.25$ × $100$

$C = 25%$

Thus, the answer is 25%.

7 0

2 years ago

•** Plss help me **•

VashaNatasha [74]

Answer:

30

Step-by-step explanation:

You can use the triangle area theorem-

15x4(/2)=30

4 0

1 year ago

What is the value of x?<br> Enter your answer in the box.<br><br> x =

larisa [96]

24^2 + 7^2 = 25^2 x = 25

5 0

2 years ago

Read 2 more answers

which fractions are equivalent to the value of 2/10 + 20/100? drag and drop the fractions into the box.

NISA [10]

Lets see

2/10+20/100
2/10+2/10
2+2/10
4/10
2/5

6 0

1 year ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

2 years ago