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3 years ago

15

Joey has a beach ball with a radius of 20 cm what's the volume of air will it hold when fully infflated

1 answer:

zysi [14]3 years ago

3 0

volume of sphere = V=(4/3)(pi)r^3

so V = (4/3) x 3.14 x 20^3 = 33,493.33 cubic cm

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Plz help me with this

Sergio [31]

9514 1404 393

Answer:

d) -4 ≤ x ≤ 1.5

Step-by-step explanation:

The domain is the horizontal extent of the graph. Here, it goes from about x=-4 to about x = 1.5.

There are solid dots on both ends of the line segment, so the inequality will use ≤ for both limits. The domain is ...

-4 ≤ x ≤ 1.5

6 0

3 years ago

PLEASE HELP! IF YOU DON'T KNOW DON'T ANSWER! 60 POINTS!!

postnew [5]

Answer:

an = 1/2 (4)^ (n-1)

a6 = 512

Step-by-step explanation:

The formula for a geometric sequence is

an = a1 (r)^(n-1)

where an is the term of the sequence

a1 is the initial term of the sequence

r is the ratio

and n is the term number

We know a1 = 1/2 and r =4

I will assume that x=6 means we want to know the 6th term

an = 1/2 (4)^ (n-1)

We want to find the 6th term

a6 = 1/2 * 4^(6-1)

a6 = 1/2 * 4^5

a6 = 512

3 0

3 years ago

Helpppp. I don’t understand

Pie

Multiply 2^(-5) by 2^6. The correct result is 2^1, or just 2 (inches).

7 0

3 years ago

Solve 5x3/4 as a mixed number, plz

lana [24]

Multiply straight across
5/1 * 3/4 = 15/4
now change it into a mixed number
3 3/4

4 0

3 years ago

Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

3 years ago