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3 years ago

Evaluate the following expression if y = 4

Mathematics

1 answer:

sleet_krkn [62]3 years ago

3 0

15+5•y/2

15+5•4 / 2

15+20 / 2

15+10

=25

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1. Write an algebra equation for each purchase. I (Mickey) bought an ice cream treat and a bottle of water for $10. Pam purchase

Ne4ueva [31]

x+y=10

x+2y=14
x is common in both so u have to subtract the second one from 1st
x-x + y-2y = 10-14
-y = -4
y=4
which means bottle of water (y) = 4
and then substitute 4 in equation (x+y=10 or x+2y=10)
x + 4 = 10
x=6

5 0

3 years ago

Graph the system of equations. {4x+4y=16 x+6y=−6 Use the Line tool to graph the lines.

tatiyna

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$4x+4y=16$ -----> equation A

$x+6y=-6$ -----> equation B

we know that

The solution of the system of equations is the intersection point both graphs

In this problem

The intersection point is $(6,-2)$

therefore

The solution is the point $(6,-2)$

using a graphing tool

see the attached figure

5 0

4 years ago

Please could you explain this step by step I’m really stuck.

allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

$\frac{5}{x + 3} + \frac4{x + 2} = 2$
$5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)$
$5 + \frac{4x + 12}{x + 2} = 2x + 6$
$5(x + 2) +4x + 12 = (2x + 6)(x + 2)$
$5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12$
$9x + 22 = 2x^2 + 10x + 12$

Let's make one side equal to 0.

$0 = 2x^2 + x - 10$

Solve by factoring, and then the zero product property.

$0 = 2x^2 + x - 10\\$

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, $ax^2 + bx + c$ , think two numbers that equal "ac" and add up to "b".