Question

Calculate the distance between the points K=-7,9 and Q= -4,3 in the coordinate plane. Round your answer to the nearest hundredth.

Answer 1

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ K(\stackrel{x_1}{-7}~,~\stackrel{y_1}{9})\qquad Q(\stackrel{x_2}{-4}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ KQ=\sqrt{[-4-(-7)]^2+[3-9]^2}\implies KQ=\sqrt{(-4+7)^2+(3-9)^2} \\\\\\ KQ=\sqrt{3^2+(-6)^2}\implies KQ=\sqrt{45}\implies KQ\approx 6.71$