Give up bro u got the rest of the questions right
Answer:
X = 3 or higher
Step-by-step explanation:
hope it helps, let me know if it doesn't :)
There are 7 math books, 9 science books and 5 literature books. Student has to select 2 books from each set.
This is a combination problem.
Number of ways to select 2 math books from 7 books = 7C2 = 21
Number of ways to select 2 science books from 9 books = 9C2 = 36
Number of ways to select 2 literature books from 5 books = 5C2 = 10
Total number of ways to select 2 books from each set = 21 x 36 x 10 = 7560 ways.
So there are 7560 ways to select 2 books from each set of seven math books, nine science books, and five literature books
Answer:
4a + 2b/3
Step-by-step explanation:
focus on 8b/12 first:
factor 8b/12 by 4 ---> 8b/12 = 4(2)b/4(3) ----> cancel 4 in the denominator and the nominator ---> 8b/12 = 4(2)b/4(3) = 2b/3
then, go back to 4a:
4a is in its simplest form, it can't be factor
therefore, plus 4a and 2b/3 = 4a + 2b/3
Pete needs one more quart of paint, leaving two quarts in total.
