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aleksandrvk [35]
3 years ago
9

Can someone help me with this I don't understand and please explain the answer

Mathematics
1 answer:
lukranit [14]3 years ago
5 0
(2^6)=1
take log on both sides,
xlog(2^6)=log(1)=0
=>
x=0, since log(2^6)>0

5^0=1
there is no value of x appearing in the equation, so x can be any valid number.
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A square patio has a perimeter of (32x+8) feet. What is the length of the patio?
kotykmax [81]
<h3>Hello There!!</h3>

<u>Given</u>

Perimeter = (32x + 8)

<u>To </u><u>Find</u>

Length of the Patio

<u>We Know,</u>

\text{Perimeter of Square = 4 × sides}

\text{ 32x + 8} = 4 \times  \text{sides} \\  \\   \fbox{dividing each side with 4} \\  \\  \implies  \text{( 32x} \div 4) + (8 \div 4) =  \frac{4 \times  \text{sides}} {4} \\  \\ \implies  \text{8x + 2} =  \frac{ \cancel4 \times  \text{sides}} { \cancel4}   \\  \\  \implies  \text{sides} = \text{8x + 2}

\therefore \text{ Length of the Patio} =  \text \red{ \underline{8x + 2 feet}}

<h3>Hope this helps!!</h3>
6 0
2 years ago
What does a semicolon in math mean
Virty [35]
A semicolon is used to separate variables from parameters. that we are defining a function of the parameters that returns a function of the variables.

5 0
3 years ago
I really need help pls
nadezda [96]

Answer:

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7 0
2 years ago
660 is 10 times as much as 600 true or false
tatiyna
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6 0
2 years ago
Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in
algol [13]

5 People can be chosen  in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

nCr=\frac{(n)!}{(n-r)!(r)!}

So here , n =13  and r=5 ,  

So after putting the value  of n and r , the equation will be

13C_5=\frac{(13)!}{(13-5)!(5)!}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}

13C_5=\frac{154440}{120}

13C_5= 1287

8 0
3 years ago
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