Option C:
The measure of arc CD is 40°.
Solution:
Given data:
m∠X = 11° and m(arc AB) = 18°
To find the measure of arc CD:
We know that,
<em>Angle formed by two intersecting secants outside the circle is equal to half of the difference between the intercepted arcs.</em>


Multiply by 2 on both sides.
22° = arc CD - 18°
Add 18° from both sides.
40° = arc CD
Switch the sides.
arc CD = 40°
Hence the measure of arc CD is 40°.
Option B is the correct answer.
Answer:
Step-by-step explanation:
Slope m = 5/6
The points (-2,1)
So; y1 = 1 and x1 = -2
The equation is y - y1 = m(x - x1)
y - 1 = 5/6(x + 2)
Multiply each term by 6
6y - 6 = 5(x + 2)
6y - 6 = 5x + 10
6y = 5x + 10 + 6
6y = 5x + 16
- 5x + 6y = 16
Multiplying by minus
5x - 6y = -16