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3 years ago

Please help me with this question

Mathematics

1 answer:

Lyrx [107]3 years ago

5 0

Answer:

Step-by-step explanation:

Here is a site to help you...that my teacher showed me...when you search it it will show this...just click graphing calculator

desmos.com

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What is the factor of -12n - 20

Arada [10]

Answer:

Step-by-step explanation:

-12n - 20

-12n = (-2)(6n)

-20 = (-2)(10)

-12n - 20 = (-2)(6n+10)

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3 years ago

HELP FAST PLEASEE<br> 3x + 5 = -16

kobusy [5.1K]

-7
The answer is -7

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2 years ago

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Dan is watching the birds in his backyard. Of the birds he watches, 9 of them, or 45%, are sparrows. How may birds are in his ba

andrezito [222]

Answer:

Step-by-step explanation:45 divided by 9 is 5

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2 years ago

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In this triangle, what is the value of x

shutvik [7]

Answer:

75.7 cm

Step-by-step explanation:

$\sin \: 63 \degree = \frac{x}{85} \\ \\ 0.8910065242 = \frac{x}{85} \\ \\ x = 0.8910065242 \times 85 \\ \\ x = 75.7355546 \\ \\ x = 75.7 \: cm$

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3 years ago

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A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c

Anna [14]

Answer:

The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

Here assume that $Z_{\frac{\alpha }{2} } \ and \ \sigma \$ is constant so

$E = \frac{k}{\sqrt{n} }$

=> $E \sqrt{n} = K$

=> $E_1 \sqrt{n}_1 = E_2 \sqrt{n}_2$

So let $n_1 = 400$ and $n_2 = 100$

=> $E_1 \sqrt{400} = E_2 \sqrt{100}$

=> $E_1 = \frac{\sqrt{100} }{\sqrt{400} } E_2$

=> $E_1 = \frac{1}{2 } E_2$

So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100

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2 years ago

Please help me with this question​

Please help me with this question