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strojnjashka [21]
3 years ago
14

Please help me with this question​

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Here is a site to help you...that my teacher showed me...when you search it it will show this...just click graphing calculator

desmos.com

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Which value of p makes the equation 18+ 2 (3p – 8) = –37 true?
Volgvan

Answer:

p = -6.5

Step-by-step explanation:

<u>Given:</u>

  • 18+ 2 (3p – 8) = –37

<u>Solving for p:</u>

  • 18+ 2 (3p – 8) = –37
  • 18 + 6p - 16 = -37
  • 6p + 2 = -37
  • 6p = -37 - 2
  • 6p = -39
  • p = -39/6
  • p = -6.5

Option 2 is correct in the list

3 0
3 years ago
How many and what type of solutions?
kolbaska11 [484]
Hello,

2k²-3k-9=0
==>k=3 or k=-3/2

Answer C two rational solutions.
3 0
3 years ago
Section 5.2 Problem 6:<br><br>Find the general solution<br><img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2
mihalych1998 [28]

Answer:

y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Step-by-step explanation:

<u>Given Second-Order Homogenous Differential Equation</u>

y''+6y'+10y=0

<u>Use Auxiliary Equation</u>

<u />m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i

<u>General Solution</u>

<u />y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Note that the DE has two distinct complex solutions p\pm qi where A and B are arbitrary constants.

4 0
2 years ago
Zoey buys A new game for $45 there is a 4% tax what will be the final cost of the game
sleet_krkn [62]
Step1. find the how much he buy he buy 45
step2. find the % the % is 4 move to decimal left 4% which is .04
step3. multilply the how much he buy or the % so this is that 45*.04=1.8
step4. what are they said they said tax is like add so we got 1.8+$45=46.8
so the answer is 46.8
look at what is the step and you understand the problem more easy way.
5 0
3 years ago
PLEASEEEE HELP ME WITH THIS ALGEBRA 1
AleksandrR [38]

Answer:

Step-by-step explanation:

total cost = tickets( c) +50

1400 = 4 (c) + 50

1350 = 4 (c)

337.50 = c

5 0
3 years ago
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