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3 years ago

How do u solve an y=mx+b equation

2 answers:

5 0

To solve a linear equation, you graph it and see where the graph intercepts the x-axis. You can either graph it on a calculator or you can set y to 0 and solve for x!

spin [16.1K]3 years ago

4 0

In order to solve for 2 unknowns in an equation, you need 2 equations.

A) 2X + 3Y = 12<span>B) 3X - 4Y = 1</span>For example, you couldn't solve for "X" and "Y" unless you had equation A AND equation B

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Carlos earns $12 an hour for 40 hours of work and $18 an hour for 6 hours of overtime. Write an expression that shows how much C

Sergeeva-Olga [200]

(12x40)+(18x6)
or
(12x40)+(18x6)=588
thank you for letting me answer and god bless <3

3 0

3 years ago

According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t

nalin [4]

Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that $p = 0.2$

Suppose that sixteen adults in the United States are selected randomly.

This means that $n = 16$

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281$

$P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126$

$P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111$

$P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981$

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

4 0

3 years ago

which description best describes the solution to the following system of equations y= -2x +3 y= -x + 1

marin [14]

For this case we have the following system of equations:
$y = -2x +3

y = -x + 1$
Equating the values of y we have:
$-2x +3 = -x + 1
$
From here, we can clear the value of x.
We have then:
$-2x + x = 1 - 3

-x = -2

x = 2$
Then, we look for the value of y.
For this, we substitute x in any of the equations:
$y = -x + 1

y = -2 + 1

y = -1$
Answer:
The ordered pair solution of the system of equations, is given by:
$(x, y) = (2, -1)$