The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
Order of operations rules are important here: n/4-13
We must do the division first. Thus, n/4-13 translates to "the quotient of n and 4, less 13."
The answer is 7.75.......
The solution would be (4,7)
X = 4 and Y = 7
