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3 years ago

The width of a rectangle is 6 2/3 inches. The length of the is twice it’s width. What so the perimeter of the rectangle?

2 answers:

Nookie1986 [14]3 years ago

6 0

$\text {Width = } 6\dfrac{2}{3} \text { inches}
$

The length is twice its width:
$\text {Length = } 2 \times 6\dfrac{2}{3} \text { inches}$

Change to improper fraction:
$\text {Length = }2 \times \dfrac{20}{3} \text { inches}$

Combine into single fraction:
$\text {Length = } \dfrac{40}{3} \text { inches}$

Find Perimeter :
$\text {Perimeter = Length + Length + Width + Width}$

$\text {Perimeter = } \dfrac{40}{3} + \dfrac{40}{3} + \dfrac{20}{3} + \dfrac{20}{3} = \dfrac{120}{3} = 40 \text { inches}$

$\bf \text {Answer: Perimeter = 40 inches}$

Dennis_Churaev [7]3 years ago

3 0

L = 2*W
L = 2 * 6 2/3 = 12 + 2*2/3 = 12 + 1 1/3 = 13 1/3
P = 2 * L + 2*W
P = 2 * (13 1/3) + 2 * 6 2/3
P = 26 2/3 + 13 1/3
P = 39 + 2/3 + 1/3
P = 40

It might be easier to understand if I used decimals. Let's try that.
L = 2 * 6 2/3 = 2 * 6.666666666 = 13.333333333
W = 6.666666666

P = 2L + 2W = 2*13.33333333 + 2*6.6666666666
P = 26.66666666 + 13.33333333
P = 40

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Step-by-step explanation:

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We know the area of a rectangle of given by = base* Height

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Upon differentiating we get

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