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nataly862011 [7]
2 years ago
13

Find the distance between the points (7,-5) and (2, -5).

Mathematics
2 answers:
vazorg [7]2 years ago
3 0

Answer:

15.62 units.

Step-by-step explanation:

To commence with, find for the vector.

Points = (7,-5) and (2,-5)

7 + 2

-5 + -5

12

-10

Vector = 12

-10

Magnitude = y² + x²

Points = (12,-10)

-10² + 12²

100 + 144

244

Square root of 244 is 15.62

Therefore, the distance between the points is 15.62 units.

Hope it helps.

iren2701 [21]2 years ago
3 0

Answer:

5

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(2 - 7)² + [-5 - (-5)]

√(-5)² + (0)²

√25

= 5

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What is the zscore with a confidence level of 95% when finding the margin of error for the mean of a normally
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Answer:

Z score with a confidence level of 95% is 1.96

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The computation of the z score with the confidence level of 95% is shown below:

While determining the margin of error for the normally distributed population from the sample, the z score of the confidence level of 95% is 1.96

The same is to be considered

Therefore the third option is correct

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Given ABCD, AC=38, and AE=3x+4, find the value of x
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D 5

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Which ordered pair represents the solution to the system of equations? {−5x+7y=−196x−2y=10
k0ka [10]
Answer:
x = 1
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Explanation:
First, solve for x by subtracting 7y from both sides of the first equation and then divide both sides by -5.

-5x + 7y = -19
-5x + 7y - 7y = -19 - 7y
-5x = -19 - 7y
-5x/ -5 = -19 - 7y/ -5
x = -19 - 7y/ -5

Next, substitute the value of x into the second equation and solve.

6 - (-19 - 7y)/ 5 - 2y = 10
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Then, solve for y

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3 years ago
Showing algebraic support, find the value of x.
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