Question

Find the distance between the points (7,-5) and (2, -5).

Answer 1

Answer:

15.62 units.

Step-by-step explanation:

To commence with, find for the vector.

Points = (7,-5) and (2,-5)

7 + 2

-5 + -5

12

-10

Vector = 12

-10

Magnitude = y² + x²

Points = (12,-10)

-10² + 12²

100 + 144

244

Square root of 244 is 15.62

Therefore, the distance between the points is 15.62 units.

Hope it helps.

Answer 2

Answer:

5

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(2 - 7)² + [-5 - (-5)]

√(-5)² + (0)²

√25

= 5