One problem with pesticide application is that if they use spray, it leaves a residue, so if a child or animal were to get in contact with the pesticide and accidentally ingest it, it could injure them.
<h2>Monosaccharides</h2>
Explanation:
Monosaccharides are the simplest form of sugars found in innumerable common food items such as honey, cane sugar, fruits
Monosaccharides are divided into two groups depending on the presence of functional groups,if aldehyde group is present then it is known aldoses and if ketone group is present then it is known as ketoses
On the basis of carbon atoms they can be classified as: triose(3),tetrose(4),pentose(5),hexose(6) and so on
a. erythrose : tetrose ketose-It is not correctly paired because erythrose is a tetrose monosaccharide which has one aldehyde group hence is an aldose
b. dihydroxyacetone : triose ketose-It is correctly paired;it is an aldose-ketose pair
c. erythrulose : tetrose aldose-It is not correctly paired because erythrulose is a tetrose monosaccharide having ketone as functional group hence is a ketose
d. fructose : hexose ketose-it is correctly paired;It is an anomer because in D-fructose carbonyl group is at C-2 hence C-2 is the anomeric carbon
e. ribose : hexose aldose-it is not correctly paired because ribose is an aldo pentose not hexose;ribose is an aldo-ketose pair
f. glyceraldehyde : triose aldose-it is correctly paired;an aldo group
Yes aftwr you can est it.
Answer :B. By changing the shape of the enzyme's active site.
check the attachment
Explanation: This is a type of inhibition , in which a molecule binds to another part of the enzyme instead of the active site.
On binding, it disrupts the normal hydrogen bond and hydrophobic interactions holding the enzyme molecule in its three dimensional shape, therefore distorting the conformation and ACTIVE SITE of the enzyme (changed it shape).
Since the active site is the precise location enzyme must bind with substrates for enzymatic reactions,this makes the enzyme not fit for binding with the substrate, therefore the efficiency is reduced. No substrate-enzyme complex, and hence no substrate-product complex for the release of products, this brings down the turnover rate and eventually
<u>the rate of reaction of the enzyme</u>
Thus, the enzyme function is totally blocked, even in high concentration of the substrate,
