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IceJOKER [234]
2 years ago
7

Answer quickly for 5 star and brainliest!

Mathematics
1 answer:
hichkok12 [17]2 years ago
6 0
The first picture is 3

The second picture is 6

The third picture is 6

The fourth picture is 1
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The area of a square with sides of 2 feet is 4 square feet. The area of a square with sides of 4 feet is 16 square feet. What eq
sattari [20]
X^2=area of a square

x squared equals the area of a square
3 0
3 years ago
Factor Completely: x^2-13x-48
salantis [7]

Answer:

Therefore,the required factors are ( x - 16 ) and ( x + 3 )is

Step-by-step explanation:

Given:

x^{2} -13x-48

To Factorize:

Solution:

First remove the factor of -48 such that you multiply the two number, the Product should be -48 and the SUM should be -13.

-48 = -16 × 3

Here, -16 and 3 are the two  required numbers

now the given expression we will split the middle term  and Factorize the given equation.

x^{2} -13x-48 =x^{2} -16x+3x-48\\\\\\\textrm{removing x common and 3 common we get}\\x^{2} -13x-48=x(x-16)+3(x-16)\\\\x^{2} -13x-48=(x-16)(x-3)

Therefore,the required factors are ( x - 16 ) and ( x + 3 )

4 0
3 years ago
What is the slope of a line that passes through (0,5) and (3,2)?
Goshia [24]

Answer:

undefine

Step-by-step explanation:

slope=2-5/3-0

-2/0

5 0
2 years ago
Mai and Noah also solved the equation, but some of their steps have errors. Fid the incorrect step in each solution and explain
cluponka [151]

Answer:

what equation

Step-by-step explanation:

3 0
2 years ago
Question is in image <br> In the diagram below, ST is parallel to PR
likoan [24]

Answer:

  D.

Step-by-step explanation:

There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.

Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...

  SQ/PQ = TQ/RQ

From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.

  (PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem

  1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division

  -PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)

  PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)

5 0
2 years ago
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