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3 years ago

Practice solving quadratic equations.

1 answer:

7 0

In order for the equation to be true, one of the factors on the left has to equal zero

So, 2x-3=0 or x-4=0 (the 3 on the left for multiplication doesn’t affect the possible answers for x)

Once you solve them, you conclude that x has to be 4 or 3/2.

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Prove that 1/log (xy)² +1/log(xy²) + log(xy³) =1 there base are x,y and z respectively.

xeze [42]

Answer:

$1/log (xy)² +1/log(xy²) + log(xy³) =1$

Step-by-step explanation:

This is your equation, right? Just checking

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3 years ago

Write a problem about a trip that can be solved by estimating fractions

Mila [183]

i wasted 4/5 of my gas for my brother

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4 years ago

Another one! please help ..

Naily [24]

Answer:

n has to be negative

Step-by-step explanation:

To solve this equation, 15 has to be subtracted from 2 which is negative

Since n is positive then the overall result will be negative

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3 years ago

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

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3 years ago

Urgent!!!! The scores of a high school entrance exam are approximately normally distributed with a given mean Mu = 82.4 and stan

Effectus [21]

Answer:95%

Step-by-step explanation:

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3 years ago

Read 2 more answers