Answer:
0.95
Step-by-step explanation:
The computation of the probability that a customer neither buys beer nor buys cigars is given below;
Given that, the probabilities are
The customers who purchased cigars be 0.02
The customers who purchased cigars + beer 0.50
And, the customers who purchased beer + cigars be 0.25
Now the probabilities where the customer purchased both
= 0.05 × 0.02
= 0.10
The probability where the customer purchased beer is
= 0.01 ÷ 0.25
= 0.04
Now the probability where a customer neither buys beer nor buys cigars is
= 1 - 0.02 + 0.04 - 0.01
= 0.95
I think C I’m not sure but if you want me to explain I multiplied 12 x 10 and 20 x 6 and they both equal 120. So then I added 120 + 120 and got 240. Then u just added 8 because 8 was never use. Which will now look like 240 + 8 and that equal 248. :)
Answer:
(-3,5)
Step-by-step explanation:
4x + 3y = 3
x − 3y = −18
Solve by addition/Elimination
x = -3
y = 5
So,
The solution of the system is (-3,5).
HELPPP PLZZ (I got you)
<u><em>Ace </em></u>
Answer:
40585818
Step-by-step explanation:
thats an insane amount of anything but like, dam n
363636*111 to find out how many were caught, then that number plus 222222
Answer:
Step-by-step explanation:
The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have
P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2
or you can find the probability of getting two odds or two evens and subtract that from 1
P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4
P(EO)=1-1/4-1/4=1/2
