What is m< DCE? A. 98 B. 85 C.34 D.102

Town B is 250 km from town A on a bearing of 080°.

Sedbober [7]

Answer:

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Zach wants to have a flower bed in his backyard he measures the area of the flower bed to be 10 square feet the actual measureme

azamat

60%? I think that what it is

7 0

3 years ago

Please help with 3 math questions ( 50 points )

Mariulka [41]

Answer:

Step-by-step explanation:

1. Reflection over the x-axis: (x, y) → (x, -y)

ΔABC with A(5, 1), B(-2, 6) C(-3, 4), after a reflection along the x-axis becomes A'(5, -1), B'(-2, -6) C'(-3, -4)

2. Counterclockwise rotation of 90° about the origin: (x, y) → (-y, x)

ΔXYZ with X(1, 2), Y(9, 7) Z(10, 1), after a counterclockwise rotation of 90° about the origin the coordinates are X'(-2,1) Y'(-7,9) Z'(-1,10)

3.

Parallelogram WXYZ with W(2, -3), X(-5, -1), Y(-1, 2), Z(6, 0), has the image after a translation of (x, y) → (x – 5, y + 2) as

W'(2-5, -3+2), X'(-5-5, -1+2), Y'(-1-5, 2+2), Z'(6-5, 0+2)

W'(-3, -1), X'(-10, 1), Y'(-6, 4), Z'(1, 2)

The coordinates of W'(-3, -1)

See Graphs...

7 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: