Answer:
Question is incomplete. it needs a topology diagram and also it needs Router R1 table. I assume User has access to the topology and Routing table.
Below Configuration will help to fix ACL problem
Hosts from the 172.16.0.0/16 network should have full access to Server1, Server2 and Server3 but this is not currently the case, as L1 can’t communicate to Server2 or Server3.
Explanation:
Following Configuration on Cisco Router R1 will help to fix all the ACL problems.
enable
configure terminal
no ip access-list standard FROM_10
ip access-list standard FROM_10
deny host 10.0.0.2
permit any
exit
!
no ip access-list standard FROM_172
ip access-list standard FROM_172
permit host 172.16.0.2
exit
!
interface GigabitEthernet0/0
ip access-group FROM_192 out
end
write memory
!
If a run-time error appears when you run a macro that has worked in the past, some part of the macro code no longer makes sense to excel, ehere run-time denotes <span> the time during which a program is running</span>
This error occurs while the program is running.
Running<span> out of memorywill results in a </span>run-time error.
Answer;
Software
Explanation;
The term hardware refers to the physical components of the computer system (as opposed to the software**). ... The primary component of the computer is the motherboard (also called the main circuit board, main logic board, mainboard, or systemboard).
**
Opposite of hardware, which describes the physical aspects of a computer, software is a generic term used to refer to applications, scripts and programs that run on a device. Software can be thought of as the variable part of a computer, and hardware the invariable part.
You would go to downloads in your library then click new folder, name it, save it, then drag it there you need it
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).