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Leya [2.2K]
3 years ago
9

Access-lists pose a logical problem which often has more than one solution. Can you think of a different set of rules or placeme

nts that would yield the same required access filtering?
Computers and Technology
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

Question is incomplete. it needs a topology diagram and also it needs Router R1 table. I assume User has access to the topology and Routing table.

Below Configuration will help to fix ACL problem

Hosts from the 172.16.0.0/16 network should have full access to Server1, Server2 and Server3 but this is not currently the case, as L1 can’t communicate to Server2 or Server3.

Explanation:

Following Configuration on Cisco Router R1 will help to fix all the ACL problems.

enable

configure terminal

no ip access-list standard FROM_10

ip access-list standard FROM_10

deny host 10.0.0.2

permit any

exit

!

no ip access-list standard FROM_172

ip access-list standard FROM_172

permit host 172.16.0.2

exit

!

interface GigabitEthernet0/0

ip access-group FROM_192 out

end

write memory

!

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1,
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Answer:

Match the methods:

See attached file

---------------------------------------------------------------------------------------------------------------------------------------

2)

Methods are public, and instance variables are private in common pattern of a class definition program.

So, the correct option is (C).

- -----------------------------------------------------------------------------------------------------------------------------------------

3) Java code:

//Create a Throttle called quiz with 100 positions<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />

Throttle quiz = new Throttle(100);

//Method that shifts quiz's flow to the halfway

quiz.shift(50);

//Display the current flow from quiz.

System.out.println(quiz.getflow());

-------------------------------------------------------------------------------------------------------

4)

Assume that the Foo class does not have a clone method. Then x is set to refer to a copy of y's object for an assignment x=y; in two Foo objects

.

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-----------------------------------------------------------------------------------------------------------------------------------------

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