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Leya [2.2K]
3 years ago
9

Access-lists pose a logical problem which often has more than one solution. Can you think of a different set of rules or placeme

nts that would yield the same required access filtering?
Computers and Technology
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

Question is incomplete. it needs a topology diagram and also it needs Router R1 table. I assume User has access to the topology and Routing table.

Below Configuration will help to fix ACL problem

Hosts from the 172.16.0.0/16 network should have full access to Server1, Server2 and Server3 but this is not currently the case, as L1 can’t communicate to Server2 or Server3.

Explanation:

Following Configuration on Cisco Router R1 will help to fix all the ACL problems.

enable

configure terminal

no ip access-list standard FROM_10

ip access-list standard FROM_10

deny host 10.0.0.2

permit any

exit

!

no ip access-list standard FROM_172

ip access-list standard FROM_172

permit host 172.16.0.2

exit

!

interface GigabitEthernet0/0

ip access-group FROM_192 out

end

write memory

!

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Answer:

import java.util.Scanner;

public class triangle {

       public static void main (String [] args) {

           int sideOne, sideTwo, sideThree;

           Scanner in = new Scanner (System.in);

           System.out.println("Enter the first side of the triangle");

           sideOne = in.nextInt();

           System.out.println("Enter the secon side of the triangle");

           sideTwo = in.nextInt();

           System.out.println("Enter the third side of the triangle");

           sideThree = in.nextInt();

           if ( sideOne<=0||sideTwo<=0|| sideThree<=0){

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           }

           else if ((sideOne + sideTwo> sideThree) || (sideOne+sideThree > sideTwo) || (sideThree+sideTwo > sideOne))

           {

               System.out.println ("The triangle is Valid");

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           else {

               System.out.println(" The Values enter are "+sideOne+ "," +sideTwo+ ","+sideThree+ " These values don't make a valid triangle");

           }

       }

Explanation:

for a Triangle to be Valid one of the three sides of the triangle must greater than the other two sides.  The code above enforces this condition using an if statement in combination with the Or Operator

The following conditions where enforced

side one, side two and side three != 0

Side One + Side Three > Side Two

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