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Viktor [21]
4 years ago
6

3       x ---- + ---- x-3 x+3 how do I solve this?

Mathematics
1 answer:
vekshin14 years ago
5 0
3/x-3+x/x+3
3(x+3)+x(x-3)/(x-3)(x+3)
3x+9+x^2-3x/(x-3)(x+3)
x^2+9/X^2-9
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3 easy questions
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Which shows a graph of a linear equation in standard form Ax + By = C, where A = 0, B is positive, and C is negative? A coordina
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Answer:

A coordinate plane with a horizontal line passing through (negative 4, negative 3), (0, negative 3) and (4, negative 3).

Step-by-step explanation:

Ax + By = C, where A = 0, B is positive, and C is negative

By= C or y= C/B which is negative

Since A is zero and C is negative, the line is parallel to x- axis and has negative value for y, so it is a horizontal line below zero

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A coordinate plane with a vertical line passing through (1, negative 4), (1, 0) and (1, 4).

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A coordinate plane with a horizontal line passing through (negative 4, negative 3), (0, negative 3) and (4, negative 3).

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8 0
4 years ago
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Answer:

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