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Zigmanuir [339]
2 years ago
8

Use the drawing tool(s) to form the correct answer on the provided number line.

Mathematics
1 answer:
suter [353]2 years ago
5 0

15x.



Follow me on BRANIY
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\frac{ x^2+6x-27 }{x-3} = \frac{ x^2+6x +3x-3x-27 }{x-3} = \frac{ x^2+9x-3x-27 }{x-3} = \\ \\ =\frac{ x(x +9 )-3(x+9) }{x-3} = \frac{ (x +9 ) (x-3) }{x-3} = x+9 \\ \\ \\ x-3\neq 0 \\x\neq 3\\D=R\setminus \left \{ 3 \right \}


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