Answer:
y-9= -3(x+2)
Step-by-step explanation:
y-y1= "M" (x-x1)
y1= 9
X1= -2
Answer:
C.
Steps:
Using points (1,0) and (0,3), you can find the slope.
3 - 0 = 3
1 - 0 = 1
3/1 = 3
5(w - 1) - 2 = 5w + 7
5w - 5 - 2 = 5w + 7
5w - 7 = 5w + 7
5w - 5w = 7 + 7
0 = 14 (incorrect)
there are no solutions to this system...0 solutions
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
All you need is mulitplication.
300 times 1.15 is 345 miles per hour.
You're welcome!
