Answer:
Stabilizer with area = 14 cm².
Step-by-step explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing = 
1/8 of the area of wing = 
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²
Step-by-step explanation:
you cannot just put the actual numbers in and calculate ?
and you can't provide the correct problem statement, as it seems.
I assume you mean
an = 3n² - 1
a sequence starts with a1, so, n>=1
a1 = 3×1² - 1 = 3-1 = 2
a2 = 3×2² -1 = 3×4 - 1 = 12 - 1 = 11
a3 = 3×3² - 1 = 3×9 - 1 = 27 - 1 = 26
a4 = 3×4² - 1 = 3×16 - 1 = 48 - 1 = 47
a5 = 3×5² - 1 = 3×25 - 1 = 75 - 1 = 74
there, that is all there is to it. you really needed help with that ?
Are you solving for X? If so, your answer will be x=-3. Hope this helps!
Answer:
<u><em>Question 1:</em></u>
The smallest 5-digit no. is <u><em>10,000</em></u>
<u>The product of its prime factors is:</u>
=> 10,000 = 2 × 2 × 2 × 2 × 5 × 5 × 5 × 5
<u><em>Question 2:</em></u>
The prime factors of 1729 are:
=> 1729 = 7 × 13 × 19
The relation between their 2 consecutive prime factor is that when they both are subtracted, they give the result 6
<u><em>Such as :</em></u>
=> 13-7 = 6
=> 19-13 = 6
Hope this helps!
Don't hesitate asking anything regarding this question!
