How do you factor 18x^2-27×+4 ? can you demonstrate it?

1 answer:

4 0

Well to factor a trinomial (Which is in the form ax^2 + bx + c) You would have to bring the A over to c so you can get x^2 alone. (If their isn't a gcf) You could also try to find what multiplys ac to add to b. but since that is not possible you would rewrite it x^2 -27x + 72 ( by multiplying the a to c) The you would rework it as normal (whatever two numbers multiply to 72 and add to -27. Which would be (x-3)(x-24). Then you would divide by the original A (x-3/18)(x-24/18). Then you would simplify that. (x-6)(x-4/3) and you would take any extra denominators and bring it to the front of the x. Making it (x-6)(3x-4)

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Given :

A graph .

To Find :

A point C that divides the segment into the ratio AC:AB= 3/4 .

Solution :

From the graph we can see that point A and B are ( 1 , -2 ) and ( 5 , 6 ) respectively .

Now , we know point which divide a line segment with end point $(x_1,y_1)$ and $(x_2,y_2)$ in m : n is :