Answer:
Option 4. 256 - 64π is the correct option.
Step-by-step explanation:
In the given picture a square is circumscribed about a circle with a side = 2r
where r is the radius of the circle.
Therefore area of the square = (2r)² = 4r² = 4 × 8² = 4 × 64 = 256 in²
Now area of the circle = πr² = π × 8² = 64π in²
Now area of region that is inside the square and outside the circle =
Area of square - area of circle = (256 - 64π) in².
Therefore the answer is (256 - 64π).
Hello! First, let's get some important information:
Luke works in the:
- week → grocery store → $16/hour
- weekend → nursery → $22/hour
Now, let's analyze the questions:
<h3>a) How much does he earn if he works 5 hours at the grocery store and 8 hours at the nursery? </h3>
To find the amount he will receive, you must multiply the amount of 1 hour by the number of hours worked. Look:
<h3>b) How much does he earn if he works g hours at the grocery store and n hours at the nursery?</h3>
<h3>c) Total pay, 5 hours at the grocery store and 8 hours at the nursery:</h3>
You'll just have to just add the value in each of the jobs:
$80 + $176 = $256
<h3>d) Total pay, g hours at the grocery store and n hours at the nursery:</h3>
Adding the values of each job:
$16g + $22n
Hope this helps!
The equation has no solution
Answer:
Before we graph 
we know that the slope, mx, could be read as 
. To graph the the equation of the line, we begin at the point (0,0). From that point, because our rise is negative (-1), instead of moving upwards or vertically, we will move downards. Therefore, from point 0, we will vertically move downwards one time. Now, our point is on point -1 on the y-axis. Now, we have 2 as our run. From point -1, we move to the right two times. We land on point (2,-1). Because we need various points to graph this equation, we must continue on. In the end, the graph will look like the first graph given.
For the equation y = 2, the line will be plainly horizontal. Why? Because x has no value in the equation. The variable 
does not exist in this linear equation. Therefore, it will look like the second graph below. We graph this by plotting the point, (0,2), on the y-axis.
