Deijah has $6.25.
Now, this 6.25 is comprised of 0.05s and 0.25s.
We know that there are 12 0.25s.
We now want to know how many remaining 0.05s there are.
Again, we know that the number of 0.05s he has, which is 12, multiplied by 0.05, plus the number of 0.25s he has, multiplied by 0.25, equals 6.25.
Thus, the answer is A, 0.25 x 12 + 0.05 x n = 6.25.
Based on what I understood, the graph would look something like this (attached as a picture). I don't know what angle it would be but I just assumed simple conditions where in the function is linear. From the given graph, the domain (x-values) would start from 10 to 40. Thus x would be equal to or greater than 10. The answer would be C.
Answer:
![f(x)=40x^2+\frac{100}{x}](https://tex.z-dn.net/?f=f%28x%29%3D40x%5E2%2B%5Cfrac%7B100%7D%7Bx%7D)
Step-by-step explanation:
Let
denote side of the square base.
Area base=Area top:
![Area=side\times side\\=x^2](https://tex.z-dn.net/?f=Area%3Dside%5Ctimes%20side%5C%5C%3Dx%5E2)
#Area of base and top is
each
Given the volume as 5 cubic feet and side of base as x, height is:
![Volume=x^2h\\5=x^2h\\h=5/x^2\\\\\therefore:\\Area \sides=4\times 5/x^2 \times x\\\\A_s=20/x](https://tex.z-dn.net/?f=Volume%3Dx%5E2h%5C%5C5%3Dx%5E2h%5C%5Ch%3D5%2Fx%5E2%5C%5C%5C%5C%5Ctherefore%3A%5C%5CArea%20%5Csides%3D4%5Ctimes%205%2Fx%5E2%20%5Ctimes%20x%5C%5C%5C%5CA_s%3D20%2Fx)
Substitute the given prices to give the function for cost of material.
Top=30cents/ft, Base=10cents/ft and sides =50cents/ft:
![f(x)=10x^2+30x^2+50(20/x)\\\\f(x)=10x^2+30x^2+\frac{100}{x}\\\\f(x)=40x^2+\frac{100}{x}](https://tex.z-dn.net/?f=f%28x%29%3D10x%5E2%2B30x%5E2%2B50%2820%2Fx%29%5C%5C%5C%5Cf%28x%29%3D10x%5E2%2B30x%5E2%2B%5Cfrac%7B100%7D%7Bx%7D%5C%5C%5C%5Cf%28x%29%3D40x%5E2%2B%5Cfrac%7B100%7D%7Bx%7D)
The function for the cost of material is expressed as:![f(x)=40x^2+\frac{100}{x}](https://tex.z-dn.net/?f=f%28x%29%3D40x%5E2%2B%5Cfrac%7B100%7D%7Bx%7D)
Answer:
mee
Step-by-step explanation:
Answer:
36/55
Step-by-step explanation:
Total 55 persons, total females 36.