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evablogger [386]
3 years ago
13

Rectangle ABCD has a perimeter of 32 units and will

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

Check below

Step-by-step explanation:

1) Check the rectangle below with a line k, the axis of rotation in the center of the figure.

2) Since it has a perimeter of 32 units and it is to be rotated about the line, the solid to be created it is a cylinder. As you can see below.

3) Let's calculate its radius, based on the information given, i.e. the perimeter:

2p=32\\2p=b+b+h+h\\2p=2(b+h)\\2(b+h)=32\\b+h=16\\b.h=60\\\\b=10\: and \:h=6

Since the line of rotation is the center, and the radius is half the line segment of the basis, then the radius is 5.

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-3.64

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3 years ago
Determine the measure of angle a. PLEASE HELP ASAP!
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Answer:

D

Step-by-step explanation:

Remember that the sum of the interior angles of a triangle will always total 180.

Therefore:

(9x+6)+(74)+(16x)=180\\

Let’s solve for <em>x: </em>

Combine LIke Terms:

(9x+16x)+(74+6)=180

Add:

25x+80=180

Subtract 80 from both sides:

25x=100

Divide both sides by 25:

x=4

Therefore, the value of <em>x </em>is 4.

Now, to find A, we can substitute it for A.

A is measured by:

\angle A=9x+6

Substitute 4 for <em>x</em> and evaluate:

\angle A=9(4)+6=36+6=42\textdegree

Hence, our answer is D.

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3 years ago
Burger town sells cheeseburgers for $7.95 each plus an additional $1.00 for each extra toppings, t. Which of the following equat
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7 0
2 years ago
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Rewrite y = x2 + x - 20 in factorized form.
Tcecarenko [31]

Answer:

y = x2 + x - 20 factors into

y = (x +5) * (x -4)

Step-by-step explanation:

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Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t &gt; 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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